🚀 go-pugleaf

Ralph,

there is no such thing as a "super instance", that's what your code implies.
Super is only supposed to allow access to super*class* members (fields,
methods and constructors). Unlike this, super does *not* denote a reference
value, hence it shouldn't compile.

Torsten

Ralph Quapp <-> schrieb in Nachricht <3ab26402$1_1@dnews>...
>Hello,
>
>I encountered a compile error in one of my classes when using the statement
>"return super;" and compiling it with javac or jikes. JBuilder does not
>complain. In my example doSomething() in class B contains this statement.
>
>The error reported is:
>
>Error in file ReturnType.java at line 31, column 37: '.' expected
>
>I am wondering now whether the statement is valid or not? And of course
why?
>
>regards Ralph
>
>
>public class ReturnType
>{
>
> public class A
> {
>  public String a = "A";
>
>  public A doSomething()
>  {
>   return this;
>  }
> }
>
> public class B extends A
> {
>  public String b = "B";
>
>  public A doSomething()
>  {
>   return super;                    <---- error
>  }
> }
>
>
> public ReturnType()
> {
>  B b = new B();
>
>  A a = b.doSomething();
> }
>
> public static void main(String[] args)
> {
>  ReturnType r = new ReturnType();
> }
>}
>
>