🚀 go-pugleaf

Use the integer as an object,,, 
instead of:
int param ;
do: 
Integer param;
then the integer will work as an object which is changed directly in
java and not copied.
example:

public void test(Integer param) { param.set(5);
}

public void example(){
        Integer example_parameter = new Integer(0);
        test( example_parameter );
        System.out.println("parameter: " + example_parameter);
}





On Mon, 19 Mar 2001 21:29:30 +0100, "John Good"
<dumster@collector.org> wrote:

>
>I've got a strange problem with Java, it's probably a feature, but please
>point me to solving this.
>
>If I have something like:
>
>public void test(int param) { param = 5;
>}
>
>and practically want to set the param to 5 (I do not want to use return,
>please!), and when I call it from another method, like:
>
>public void example(){
>        int example_parameter = 0;
>        test( example_parameter );
>        System.out.println("parameter: " + example_parameter);
>}
>
>I'll get the 0 as the output, and I want 5; how to assign a value a
>parameter? (pointers I miss you ;)
>I've checked some books on that, but as allways its not in it, because it's
>"too obvious"...
>
>plz help :)
>
>