🚀 go-pugleaf

You have to assign the actual array first.
What you actually have now is only a reference
to a string array which has not yet been initialized.
You can initialize an array by doing the following:
String[] myArray = new String[size]; wher size is the
size of the array.
Or you can also fill up the array directly by doing
this:
String[] addressLine = {"0", "1", "2", "3", "4", "5", "6"};

Here is your code snippet again.
    String[] addressLine = new String[7]; //the size is 7
    for(int i=0; i<7; i++){
      addressLine[i]= new String("xxx" + i);
    }
    //print out the content of the array
    for(int j=0; j<7; j++){
      System.err.println(addressLine[j]);
    }

Regards,

Marcel


Thomas682 wrote:

> hi,
>
> String AddressLine[];
>
> for(int i=0;i<7;i++)
>           AddressLine[i]= new String("xxx");
>
> no compile error but runtime exception-(Not exists)
>
> hmmmmm - Malloc( ?????
>
> Thanks for Help
>
> Thomas
>
> "Tor Iver Wilhelmsen" <tor.wilhelmsen@sds.no> wrote in message
> news:uu254bq17.fsf@sds.no...
> > "Harry Whitehouse" <harry@envmgr.com> writes:
> >
> > >  String AddressLine[];
> >
> > Note that this only declares the reference, it does not assign an
> > actual array to it.
> >
> > >  for(int i=0;i<7;i++)
> > >          AddressLine[i]= new String;               // line 208
> >
> > Unlike C++ and C#, constructors in Java need a parenthesis also when
> > there are no arguments to the constructor. Also, String doesn't have a
> > no-args constructor, so you need an argument.