How do you have the user input an integer using JOptionPane.showInputDialog

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2 total messages Started by DementiaT Sat, 20 Dec 2003 09:08

#1409

Author: DementiaT
Date: Sat, 20 Dec 2003 09:08

19 lines
1862 bytes

Beginner here :)

Im trying to do just that...have the user enter an integer into the
dialog box...

my code is:
...

int invQty;

invQty = JOptionPane.showInputDialog (null, "What is the quantity of
\"" + invName + "\"?","Enter Quantity", JOptionPane.QUESTION_MESSAGE);

...

I get an incompatible type error...  it seems
JOptionPane.showInputDialog  only accepts strings?

Thanks :)

Re: How do you have the user input an integer using JOptionPane.showInputDialog

#1410

Author: Craig Simmons
Date: Sat, 20 Dec 2003 14:49

40 lines
2343 bytes

Hi

What you want to do is...

int invQty;
String retValue =  JOptionPane.showInputDialog (null, "What is the quantity
of
\"" + invName + "\"?","Enter Quantity", JOptionPane.QUESTION_MESSAGE);

try{
    invQty = Interger.parseInt(retValue);
catch(NumberFormatException x){
    //handle error
   }

Craig

"DementiaT" <dementiat@high.net> wrote in message
news:o548uvshiobdff6str8j1rgvc5o25oqd3f@4ax.com...
: Beginner here :)
:
: Im trying to do just that...have the user enter an integer into the
: dialog box...
:
: my code is:
: ...
:
: int invQty;
:
: invQty = JOptionPane.showInputDialog (null, "What is the quantity of
: \"" + invName + "\"?","Enter Quantity", JOptionPane.QUESTION_MESSAGE);
:
: ...
:
: I get an incompatible type error...  it seems
: JOptionPane.showInputDialog  only accepts strings?
:
: Thanks :)
:
:

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