🚀 go-pugleaf

In article <3ooo33$q17@isp1.isp.net> scooper@denkart.com (Steven M. Cooper) writes:
>Dan (kolohe@rahul.net) wrote:
>
>: Grep "string" *  returns lines containing the string preceded with the
>: filename:
>:               filea:"xxxxxxxxxxstringxxxxxxxxxxxx"
>:               fileb:"xxxxxxxxxxxxxxxxxxstringxxxx"
>:               etc.
>
>: Unfortunately, 'head -20 * |grep "string"  will not return the file name
>: because grep operates on the results from 'head'.  Anyone know of a way
>: to restrict grep to search only the first 20 lines of a file OR a way
>: to make the head/grep piped command display the filename?
>
>As is typical with UNIX, there are dozens of ways to do this, all of
>which are cryptic.  One way would be to "cut" out the first field of
>grep's output, telling it that the "field" is delimited by a colon.
>"cut" is a good way to do vertical slicing; "head" and "tail" do
>horizontal slices.  Anyway, try:
>
>grep "string" * | cut -f1 -d:
>
>There are options to grep if you only want a file listed once.

I think the original poster seeks a way to RETAIN the file name portion.
I'd recommend writing a small awk program looking like the following:

FNR <= 10 && $0 ~ /string/ { print FILENAME ":" $0 }

Sorry, I'm still an awk beginner and I may be worng.
Good luck!

hiro
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Hiro Sugawara       hsugawar@us.oracle.com   +1(415)506-9336
Oracle Corporation      MPD - Massively Parallel Development
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