🚀 go-pugleaf

deal4428-

> so x a member of *Z,    x=five hundred fifty three billion nine hundred
> seventy seven million seven hundred seventy seven thousand seven hundred
> fifty seven
> now LiN(x)

a_1=LiN(553 977 777 757)=114
a_2=LiN(LiN(553 977 777 757))=LiN(114)=18
a_3=LiN(LiN(LiN(553 977 777 757)))=LiN(LiN(114))=LiN(18)=8
a_4=LiN(LiN(LiN(LiN(553 977 777
757))))=LiN(LiN(LiN(114)))=LiN(LiN(18))=LiN(8)=5
a_5=LiN(LiN(LiN(LiN(LiN(553 977 777
757)))))=LiN(LiN(LiN(LiN(114))))=LiN(LiN(LiN(18)))=Lin(LiN(8))=LiN(5)=4
a_n=LiN(4)=4 (n>5)

Travis J. Willse
sal-crumb@geocities.com


> now what  is a_n
> and what is going to limit?
>
> ----- Original Message -----
> From: Willse <gbtt@email.msn.com>
> Newsgroups: can.rsc.mathsci
> Sent: Monday, October 11, 1999 7:27 PM
> Subject: Letters in the Name function
>
>
> > All-
> >
> > Consider the function (whose domain is members of the set Z*, the set of
> > nonnegative integers) defined by
> >
> > LiN(x)={letters in the formal English name of x}
> >
> > For example, LiN(8)=5, because "eight" has five letters.
> >
> > LiN(x) for the first few values of {0,1,2,...} are
> > {4,3,3,5,4,4,3,5,5,4,3...}.
> >
> > Prove (or disprove) that, regardless of the initial value of x,
> >
> > {lim n->+oo}[a_n=LiN(x) if n=1, a_n=LiN(a_(n-1)) if n>1]=4
> >
> > Travis J. Willse
> > sal-crumb@geocities.com
> >
> >
> >
> Willse <gbtt@email.msn.com> wrote in message
> news:#mAdbiEF$GA.234@cpmsnbbsa05...
> > All-
> >
> > Consider the function (whose domain is members of the set Z*, the set of
> > nonnegative integers) defined by
> >
> > LiN(x)={letters in the formal English name of x}
> >
> > For example, LiN(8)=5, because "eight" has five letters.
> >
> > LiN(x) for the first few values of {0,1,2,...} are
> > {4,3,3,5,4,4,3,5,5,4,3...}.
> >
> > Prove (or disprove) that, regardless of the initial value of x,
> >
> > {lim n->+oo}[a_n=LiN(x) if n=1, a_n=LiN(a_(n-1)) if n>1]=4
> >
> > Travis J. Willse
> > sal-crumb@geocities.com
> >
> >
> >
>
>