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Article #44Re: help
From: carbonbasetwo
Date: Fri, 31 Mar 2000 00:00
Date: Fri, 31 Mar 2000 00:00
152 lines
5920 bytes
5920 bytes
Virgil... I ran through your calc....two answers exists to this problem depending on how it is read. 36000 and 42000 6000 and 7000 Bummer of a question!!! Anthony carbonbasetwo <carbonbasetwo@email.msn.com> wrote in message news:#$QwVG1m$GA.265@cpmsnbbsa05... > The question is phrased: > > 1st son gets 1000 + 1/7 of what is left of entire estate at that moment. > Then > 2nd son gets 2000 +1/7 of what is left of entire estate at that moment. > > estate = z > In other words the second son is getting: z-1000+1/7-2000+1/7... > > Like this: > > 1. 1000+1/7x = 2000+1/7y > 2. y = x-1/7-1000 > > New Equation: > > 1000+1/7x = 2000+1/7x(x-1/7x-1000) > 1000+1/7x = 2000+1/7x(6/7x-1000) > 1000+1/7x = 2000+6/49x-142.86 > 1/7x-6/49x = 2000-142.86-1000 > 1/49x = 857.14 > x = 41999.86 or 42000.0000 > > Now back in the original equation: > > 1st son: 1000+1/7(42000.0000)=1000+6000=7000 > 42000-7000=35000 > 2nd son: 2000+1/7(35000.0000)=2000+5000=7000 > 35000-7000=28000 > 3rd son: 3000+1/7(28000.0000)=3000+4000=7000 > 28000-7000=21000 > 4th son: 4000+1/7(21000.0000)=4000+3000=7000 > 21000-7000=14000 > 5th son: 5000+1/7(14000.0000)=5000+2000=7000 > 14000-7000=7000 > 6th son: 6000+1/7(7000.0000)=6000+1000=7000 > > NOW NO MONEY IS LEFT.... THIS IS THE PROOF........ > > Anthony > > Virgil <vmhjr@frii.com> wrote in message > news:vmhjr-5AB1B9.21133230032000@news.frii.com... > > I have rechecked my work, and found it correct according to the > > statement of the problem as I understand it. > > The nth son in turn gets a fixed amount, $1000*n, plus a fixed share, > > 1/7, of what is left after his elder brother's shares and his own fixed > > amount have been subtracted from the original estate. This is supposed > > to give each son the same dollar amount. > > > > Mr/Miz carbonbasetwo's solution does not follow these rules, his eldest > > son does not get his $1000 first and then his 1/7, he only gets a 1/7 > > share. > > > > If you start with 36 in thousands of dollars: > > The first son gets 1 plus 1/7 of what is left after paying the 1. > > This is 1 + (36 - 1)/7 = 1 + 5 = 6 leaving 30. > > The second son gets 2 plus 1/7 of what is left after paying the 2. > > This is 2 + (30-3)/7 = 6 leaving 24. > > The third son gets 3 + (30 - 3)/7 = 2 + 4 = 6 leaving 18. > > The fourth son gets 4 + (18-4)/7 = 6 leaving 12. > > The fifth son gets 5 + (12-5)/7 = 6 leaving 6. > > The sixth son gets 6 + (6-6)/7 = 6 leaving 0. > > As you can see, each son gets 6 in thousands of dollars. > > > > > > But if you start with 42 in thousands of dollars: > > The first son gets 1 plus 1/7 of what is left after paying the 1 k$ > > This is 1 + (42 - 1)/7 = 1 + 41/7 = 6+6/7 leaving 35+1/7. > > The second son gets 2 + (35 1/7 -2)/7 = 2+34/49 leaving 32+22/49. > > > > Note that even the first two sons get different amounts. Thus this > > cannot be a solution with all sons getting equal amounts. Furthermore, > > the amount left goes form positive to negative without ever being zero. > > > > > > > > In article <uX$ifoqm$GA.60@cpmsnbbsa05>, "carbonbasetwo" > > <carbonbasetwo@email.msn.com> wrote: > > > > >IT SURE WILL.... YOU BETTER CHECK YOU CALCULATION > > > > > > > > >42,000/6 = $7000 Sounds like an equal share to me... > > > > > >Your calc is wrong... here is the correct way to calc son one.... > > > > > >1000+1/7x = 2000+1/7y > > > > > >Then find for quantity in terms of x. > > > > > > > > >Then you will get the answer.... I will send more after your response.] > > > > > >Anthony > > > > > > > > > > > >Virgil <vmhjr@frii.com> wrote in message > > >news:vmhjr-76DBF2.17222428032000@news.frii.com... > > >> In article <OCKfvROm$GA.225@cpmsnbbsa03>, "carbonbasetwo" > > >> <carbonbasetwo@email.msn.com> wrote: > > >> > > >> >$42000 > > >> > > > >> >6 sons > > >> > Kevin Rowe <kevin.rowe2@tesco.net> wrote in message > > >> > news:8blr4e$lhq$1@barcode.tesco.net... > > >> > When an old man dies, his sons gather at the lawyers office to hear > > >> > his > > >> > will read out. > > >> > > > >> > The 1st son was given 1000 + 1/7 of what was left. The second son > was > > >> > given 2000 + 1/7 of what was left. The 3rd son was given 3000+ 1/7 > of > > >> > what was left. and so on. > > >> > > > >> > They all recieved the same amount of money. > > >> > > > >> > > > >> > How much money was there in total? > > >> > > > >> > How many sons were there? > > >> > > > >> > > > >> > Good luck > > >> > kev@tokenmusic.co.uk > > > > -- > > Virgil > > vmhjr@frii.com > >
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X-Google-Language: ENGLISH,ASCII-7-bit X-Google-Thread: f458d,77e39852d8b682dd X-Google-Attributes: gidf458d,public X-Google-Thread: 146cab,77e39852d8b682dd X-Google-Attributes: gid146cab,public X-Google-Thread: fd6c7,77e39852d8b682dd X-Google-Attributes: gidfd6c7,public X-Google-Thread: f64ed,77e39852d8b682dd X-Google-Attributes: gidf64ed,public X-Google-Thread: 1162a1,77e39852d8b682dd X-Google-Attributes: gid1162a1,public X-Google-Thread: 106622,77e39852d8b682dd X-Google-Attributes: gid106622,public X-Google-Thread: 112e06,77e39852d8b682dd X-Google-Attributes: gid112e06,public From: "carbonbasetwo" <carbonbasetwo@email.msn.com> Subject: Re: help Date: 2000/03/31 Message-ID: <#Ujr8r2m$GA.198@cpmsnbbsa04> X-Deja-AN: 605036993 References: <8blr4e$lhq$1@barcode.tesco.net> <OCKfvROm$GA.225@cpmsnbbsa03> <vmhjr-76DBF2.17222428032000@news.frii.com> <uX$ifoqm$GA.60@cpmsnbbsa05> <vmhjr-5AB1B9.21133230032000@news.frii.com> <#$QwVG1m$GA.265@cpmsnbbsa05> X-Priority: 3 X-MimeOLE: Produced By Microsoft MimeOLE V5.00.2615.200 X-MSMail-Priority: Normal Newsgroups: can.rsc.mathsci,uk.education.maths,uog.mathstat.63-436,ut.mathsci,uw.math.mathsoc,york.mathstat.course.math2221,york.mathstat.course.math4100