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Article #166Re: Cyclic Quadrilateral Problem
From: David
Date: Mon, 31 Mar 1997 00:00
Date: Mon, 31 Mar 1997 00:00
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landmark@vcn.bc.ca (Scott Phung) wrote: Scott, a cyclic quadrilateral is formed as *any* four distinct points on the circle. The area is not fixed in any way, and the center of the circle may be far from the intersection of the diagonals. You can find the area generally only as the area of the quadrilateral. Being cyclic adds no distinct differences to that figure so far as area is concerned, although there is a wealth of other properties, such as "A cyclic quadrilateral that is a parallelogram must be a rectangle." ..in which case the center of the circle *would* coincide with the intersection of diagonals. David. If knowledge is power, that explains my weakness. :-)
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X-Google-Language: ENGLISH,ASCII-7-bit X-Google-Thread: 1077c2,2685f1246c1c8405 X-Google-Attributes: gid1077c2,public X-Google-Thread: f7972,2685f1246c1c8405 X-Google-Attributes: gidf7972,public X-Google-Thread: 1130d6,2685f1246c1c8405 X-Google-Attributes: gid1130d6,public From: margot@cnwl.igs.net (David) Subject: Re: Cyclic Quadrilateral Problem Date: 1997/03/31 Message-ID: <5hooqn$ikg$1@nntp.igs.net> X-Deja-AN: 229661054 References: <5hnv2g$95s@opus.vcn.bc.ca> Organization: IGS - Information Gateway Services Newsgroups: can.schoolnet.math.sr,alt.math.recreational,alt.uu.math.misc