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Article #170Re: math question
From: Theodore Bush
Date: Tue, 01 Apr 1997 00:00
Date: Tue, 01 Apr 1997 00:00
33 lines
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1395 bytes
Hi Tracy! Let the number we are trying to find be called x (boy thats original huh?) Well then, half that number (x) would be x/2. 3 times that number would be 3x Finally 10 more than three times the number would be 10 + 3x One key word in the problem is the word "is". read this as equal to. So <Half of a number> <is> <10 more than three times the number> x/2 = 10 +3x Now we have an equation to solve! x/2 = 10 + 3x <multiply each side by 2> x = 2(10 + 30x) x = 20 + 6x <subtract 6x from both sides> -5x = 20 <divide by -5> x = -4 Ted Bush kn7h@worldnet.att.net CENTURYinter.net <bert1miller@centuryinter.net> wrote in article <5hpv44$nd3@news.ld.centuryinter.net>... > > > > im in 8th grade and were learning about problem solving with equations. one of the problems is: half of a number is 10 more than three times the number. > how are you supposed to figure this out? i would appreciate the help. > thanks > tracy >
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X-Google-Language: ENGLISH,ASCII-7-bit X-Google-Thread: f7972,dba1e6b40b460119 X-Google-Attributes: gidf7972,public From: "Theodore Bush" <kn7h@worldnet.att.net> Subject: Re: math question Date: 1997/04/01 Message-ID: <01bc3edf$4bbae560$b0a893cf@busht> X-Deja-AN: 229945526 References: <5hpv44$nd3@news.ld.centuryinter.net> Organization: AT&T WorldNet Services Newsgroups: can.schoolnet.math.sr