🚀 go-pugleaf

margot@cnwl.igs.net (David) wrote:
D> landmark@vcn.bc.ca (Scott Phung) wrote:
D>
D>
D> Scott,  a cyclic quadrilateral is formed as *any* four distinct points
D> on the circle.  The area is not fixed in any way, and the center of
D> the circle may be far from the intersection of the diagonals.  You can
D> find the area generally only as the area of the quadrilateral.  Being
D> cyclic adds no distinct differences to that figure so far as area is
D> concerned, although there is a wealth of other properties, such as "A
D> cyclic quadrilateral that is a parallelogram must be a rectangle."
D> ..in which case the center of the circle *would* coincide with the
D> intersection of diagonals.
D>
D> David.
D> If knowledge is power, that explains my weakness.  :-)

David,

The vertices can be on *any* four distinct points?
But then does the diagonaly opposite angles add up to 180?

If it does, my mistake, and I will beleive that what your saying
is correct.

Or maybe becuase the vertices lie on the circle makes the
diagonally opposite angles add to 180.


Thanks,
Scott Phung.

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