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Article #52Re: Stuck on another problem
From: Patrick
Date: Wed, 11 Nov 1998 00:00
Date: Wed, 11 Nov 1998 00:00
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1283 bytes
First isolate a variable in one of the equations, for this example I chose to isolate x from the first equation. 1) x=z-y Isolate a second variable from a second equation. 2) y=6-z-3x Substitute the value for x in 1) into 2), giving you: 3) y=-3+2z Isolate the same variable y in the third equation 4) y=x+2z-5 Substitute 1) into 4) giving: 5) y=(3z-5)/2 Now since 3) and 5) are both equal to y, they are also equal 6) -3+2z=(3z-5)/2 Isolate z and you should get z=1 Plug that in to the equations of your choice to get x and y x=2 y=-1 There you go.
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X-Google-Language: ENGLISH,ASCII-7-bit X-Google-Thread: 11516a,bc266ada455dd446 X-Google-Attributes: gid11516a,public X-Google-Thread: f7972,bc266ada455dd446 X-Google-Attributes: gidf7972,public From: "Patrick" <cmpeng@escape.ca> Subject: Re: Stuck on another problem Date: 1998/11/11 Message-ID: <sR422.395$aO5.465@typhoon.mbnet.mb.ca> X-Deja-AN: 410509056 References: <364763BD.E49F976A@home.com> X-MimeOLE: Produced By Microsoft MimeOLE V4.72.3110.3 X-Trace: typhoon.mbnet.mb.ca 910744024 207.161.63.89 (Tue, 10 Nov 1998 18:27:04 CDT) Organization: MBnet Networking Inc. NNTP-Posting-Date: Tue, 10 Nov 1998 18:27:04 CDT Newsgroups: can.schoolnet.math.sr,alt.math.undergrad