Re: limits

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#63

From: mathedman
Date: Sun, 06 Dec 1998 00:00

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In article <3669B0C4.7B7D@mail.com>,
  pez <hot@mail.com> wrote:
> how do you do this?
>
> lim    [tan(3x)]/2x
> x->0
>
> I thought of using
>
> lim    sin(3x)/[cos(3x)2x]
> x->0
>
> but then what?
>
> thanx in advance
>                  -PeZ

   Try l'Hospital's Rule
>

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Subject: Re: limits
Date: 1998/12/06
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