🚀 go-pugleaf

sandy.tan@ablelink.org (Sandy Tan) wrote:

>How does one integrate 'ln x'?

I think it's
x*ln(x)-x

The way to do this is to use the integral(u*dv)=uv-integral(v*du)
so
u  = ln(x)
du = 1/x
v  = x
dv = 1

=x*ln(x)-integral(x/x)
=x*ln(x)-integral(1)
=x*ln(x)-x

It's been about 6 months since I've even looked at integration, so I
don't know if that's right, or if I'm totally out to lunch... don't do
it on a test or anything, eh?

 - Executioner/[Independent]
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