Certain p-series...

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#786

From: Hugh Alan Grant
Date: Wed, 13 Dec 1995 00:00

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	Hello.  In a calculus textbook I own, it is stated that:
 
 1 + 1/4 + 1/9 + 1/16 + ... + 1/(n^2)+ ... = ((pi)^2)/6,

1 + 1/8 + 1/27 + 1/64 + ... + 1/(n^3) + ... = 1.2020569031, and

1 + 1/16 + 1/81 + 1/256 + ... + 1/(n^4) + ... = ((pi)^4)/90.

	Does anyone know how these sums would be calculated?

Hugh Grant

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From: Hugh Alan Grant <umgran22@CC.UManitoba.CA>
Subject: Certain p-series...
Date: 1995/12/13
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