Re: Integration of 'ln x'

Article View: can.schoolnet.math.sr

Article #797

Back to can.schoolnet.math.sr Previous Next

#797

From: Luis A. Dissett
Date: Sat, 23 Dec 1995 00:00

16 lines
782 bytes

In article <1e.750.441@ablelink.org> sandy.tan@ablelink.org (Sandy Tan) writes:

> How does one integrate 'ln x'?

By parts. :-)

Luis.

P.S. Seriously now: use the formula

	I(u dv) = uv - I(v du)

     taking u = ln x, v = dx

     This gives I(ln x dx) = x ln x - I(x (1/x dx)) = x ln x - I(dx) =
                             x ln x - x + C

Technical Details

Message-ID: <LDISSETT.95Dec23110935@qew.cs.toronto.edu>

Path: arc1-ca.pugleaf.net!unknown!not-for-mail

References: <1e.750.441@ablelink.org>

Show Full Headers

Complete Article Headers

X-Google-Language: ENGLISH,ASCII-7-bit
X-Google-Thread: f7972,8116d76b28117bb8
X-Google-Attributes: gidf7972,public
From: ldissett@qew.cs.toronto.edu (Luis A. Dissett)
Subject: Re: Integration of 'ln x'
Date: 1995/12/23
Message-ID: <LDISSETT.95Dec23110935@qew.cs.toronto.edu>
X-Deja-AN: 122666726
x-nntp-posting-host: qew.cs.toronto.edu
references: <1e.750.441@ablelink.org>
newsgroups: can.schoolnet.math.sr

Reply to Parent Message