🚀 go-pugleaf

rick@combdyn.com (Rick Link) writes:
[...]
>v = sqrt(qmg/CAp)

>For q = 0.5, m = 90 kg, g = 9.81, C = 1.0, A = 2 m^2, and p = 1.118 kg/m^3,
>you get v = 14 m/sec, which means he could run 100 m in 7.14 sec (take that,
>Ben Johnson).

Nice approach, Rick.  But really, 14m/s is not very fast.  I think a 
major improvement would be to use A=1m^2 instead of 2m^2, the latter 
being the projected cross section of a very large human indeed.  (What? 
two meters tall by ONE METER ACROSS???)

With that adjustment you would get a velocity of around 20m/s, or 1.41 
times your own result.  Still low, I think, but better.  (Cheetahs can 
do twice that.)

But then, I guess including Superman's cape might make the area closer to 
2m^2...  Hmmm...  Why don't we just ask Superman?  :-)

(And now, a little advertising: Don't forget to vote on the new condensed 
matter physics newsgroup -- sci.physics.cond-matter.  Send any e-mail to 
<physics-cfv-request@netagw.com> for an automatically generated CFV and 
ballot for voting.)

...John
  _____    
 |     |    _____    "Come on!  Jesus needs a new pair of shoes!!!"
 |  O  |   |O   O|                  -- God (playing dice with the Universe)
 |     |   |O   O|   
  ~~~~~    |O   O|   John P. Kondis        UC Irvine        jkondis@uci.edu
            ~~~~~