🚀 go-pugleaf

In article <1991Jun13.234834.22970@neon.Stanford.EDU> andy@DEC-Lite.Stanford.EDU (Andy Freeman) writes:
>In article <396@validgh.com> dgh@validgh.com (David G. Hough on validgh) writes:
>>      do 30 i = 2,n
>>         if(abs(dx(i)).le.dmax) go to 30
>>         isamax = i
>>         dmax = abs(dx(i))
>>   30 continue
>

	Motorola's DSP 96000 family has some instructions that would help this
loop out a lot. They have conditional assign, and two moves per instruction.

I think the code for this loop could be done with the following instructions
(I don't know the exact mnemonics, but here's the general idea):


	int abs1=dx(0)
	i=&dx[2]

lp:	set abs1=abs(abs1). fetch *(i++) to abs2
	compare abs1 to dmax
	conditionally store i to isamax and abs1 to dmax
	
	set abs2=abs(abs2). fetch *(i++) to abs1
	compare abs2 to dmax
	conditionally store i to isamax and abs2 to dmax

	6 instructions for 2 iterations ain't bad. you'd have to do one SUB at
the end to correct isamax to be i instead of &dx[i]. zero overhead looping handles
the iteration.

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