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Article #339

Questions on standard IEEE 802.3

#339
From: Stefan Petri
Date: Tue, 05 Jan 1993 15:36
28 lines
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What is the reason for permitting only three coax segments on the
maximum transmission path between any two stations instead of five?
This question arises because the end-to-end propagation delay of a
link segment should be less than 2570ns instead of the end-to-end
propagation delay of a coax segment of 2165ns (10Base5).

The IEEE 802.3 standard reads in section  8.6.1 (5) as follows:
   The maximum transmission path permitted between any two stations
   is five segments, four repeater sets (including optional AUIs),
   two MAUs, and two AUIs. Of the five segments a maximum of three
   may be coax segments; the remainder are link segments.

   The maximum transmission path consists of: 5 segments, 4 repeater
   sets (with AUIs), 2 MAUs, and 2 AUIs. The total number of
   segments equals the number of link segments plus the number of
   coax segments.  If there are two link segments on the
   transmission path, there may be a maximum of three coax segments
   on that path. If there are no link segments on a transmission
   path, there may be a maximum of three coax segments on that path
   given current repeater technology.

Does the term `current repeater technology' mean that a delay caused
by an inter repeater link (IRL) is negligible compared to the delay
of a repeater set between two coax segments?

Any help is much appreciated. If possible, please answer via E-Mail.

Stefan
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From: petri@ibr.cs.tu-bs.de (Stefan Petri)
Subject: Questions on standard IEEE 802.3
Message-ID: <1993Jan5.153625.21334@ibr.cs.tu-bs.de>
Originator: petri@diana.ibr.cs.tu-bs.de
Sender: postnntp@ibr.cs.tu-bs.de (Mr. Nntp Inews Entry)
Reply-To: petri@ibr.cs.tu-bs.de (Stefan Petri)
Organization: TU Braunschweig, Informatik (Bueltenweg), Germany
Date: Tue, 5 Jan 1993 15:36:25 GMT
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