void* type

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#2304

From: Huayong Yang
Date: Sat, 16 Mar 1996 16:22

21 lines
837 bytes

I know void* means an arbitrary pointer. In an interview, I was asked to
write a routine that swaps two pointers.

I tried with this

void Swap(void** p1, void** p2)
{
  void* p = *p1;
  *p1 = *p2;
  *p2 = *p;
}

but it is not correct, because void* is not allowed as operand.

How should I do?

--
Huayong

WWW home pages:                           Email:
http://www.math.umass.edu/~yang           yang@math.umass.edu

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From: yang@math.umass.edu (Huayong Yang)
Newsgroups: comp.lang.c.moderated
Subject: void* type
Date: 16 Mar 1996 10:22:06 -0600
Organization: UMass/Amherst Dept Math & Stats
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