🚀 go-pugleaf

Yourname@somwhere.COM (Your Name) writes:

Do people who are on a first name basis with you just call you "Your"?

> >Node ***nodedata=NULL;
> >int xnodes,ynodes,znodes;
> >
> >Here's how I allocate the array:
> >
> >nodedata = (Node ***)malloc(sizeof(Node **) * xnodes);
> >for(i = 0;i < xnodes;i++){
> >    nodedata[i] = (Node **)malloc(sizeof(Node *) * ynodes);
> >    for(j = 0;j < ynodes;j++)
> >       nodedata[i][j] = (Node *)malloc(sizeof(Node) * znodes);
> >}
> >

>I've never seen anything like that before!  Assuming all you need is
>a 3D array, why not:

>nodedata = (Node *) malloc(sizeof(Node) * x_dim * y_dim * z_dim);

>then refer to each element as nodedata[i][j][k]?

Maybe because this will not work? If both "y_dim" and "z_dim" are 
compile time constants, you could do something like

  Node (* nodedata)[y_dim][z_dim];

  nodedata = malloc(sizeof(Node) * x_dim * y_dim * z_dim);

Now you can use the notation proposed by "Your"

>To free use:

>free(nodedata);

>Also, I think I've heard that once the OS has allocated the memory,
>it stays allocated to the process even though the program has
>freed it.  The memory is, of course, available for future allocation.

This is true for a lot of systems I know.

Kurt
--
| Kurt Watzka                             Phone : +49-89-2180-6254
| watzka@stat.uni-muenchen.de
| ua302aa@sunmail.lrz-muenchen.de