🚀 go-pugleaf

In article <4jv7ge$d49@solutions.solon.com>, davis@space.mit.edu (John E. Davis) writes:

[on different pointer representations]

|> So, does this fail:
|> 
|>    double *d;
|>    char *p;
|>    unsigned int size;
|>    
|>    size = sizeof (double);
|>    d = malloc (size);
|>    p = malloc (size);

If you have correctly prototyped malloc, of course not.  Malloc returns
a void * and the C compiler does a type conversion to the appropriate type.
Just like

# include <math.h>

{
	int i = sin (0);
}

|> Is malloc smart enough to know
|> which representation to return?

No, but it is guaranteed to return a value that can be converted to a pointer
of any type.

Konrad Schwarz