🚀 go-pugleaf

From article <STABL.90Sep19204925@trillian-gw.fmi.uni-passau.de>, by stabl@unipas.fmi.uni-passau.de (Robert Stabl):
> In article <26470@boulder.Colorado.EDU>, dennis@boulder.Colorado.EDU (Dennis Heimbigner) writes:
>> [Omitted discussion where Dennis wants to create a function dynamically,
>>  by adding (or removing) input/output information to (or from) the
>>  function at run time.]

Dennis originally asked for something analogous to Prolog's database
manipulated with assert and retract. Since this is 'state', and purely
functional systems are stateless, you obviously can't have it. Variables
do not change their values over time; and since a named function is just a
variable bound to a 'function value', that variable must represent the
same function for the life of the variable. [This is very basic stuff
and is provided only for the benefit of novice functional programmers.]

[BTW, the charter of this newsgroup forbids discussion of imperative
 features found in some 'impure' functional languages. So SML references
 are out for now.]

> [Now, Robert provides a SML example that illustrates what he thinks
>  Dennis wants. I've omitted some SML responses for brevity.]
> 
> - exception unbound;   (* needed for undefined values *)
> 
> - fun update f (x, y) = fn n => if (n = x) then y else f (n);
>                        (* this function updates f with the new pair (x, y) *)
> 
> - fun raise_unbound x = raise unbound;
>                        (* The first update uses this function *)
> 
> - val f = update raise_unbound (1, 2);
>                        (* the first pair *)
> 
> - val f = update f (17, 9);
>                        (* the next one *)
> 
> - val f = update f (23, ~1);
>                        (* and so on *)
> 
>  (* now the application of f *)
> - f(17);
>> val it = 9 : int
> 
> - f(23);
>> val it = ~1 : int
> 
> - f(3);
>> uncaught exception unbound

The choice of names in this example may confuse some novice functional
programmers. First, the function 'update' really doesn't update
anything: It merely creates a new function value that is a little more
defined than the function value passed to it. Second, the three
'val f = ...' expressions are not destructively updating f: Each f
is a _different_ name--you might as well have called them f1, f2, and f3.
The command interpreter creates a new lexical scope for each definition
of f. Think of the above example as

    let
       f = update raise_unbound (1, 2)
    in
       let
          f = update f (17, 9)
       in
          let
             f = update f (23, ~1)
          in 
             [f(17),f(23),f(3)]
          end
       end
    end

I hope this clarifies things somewhat. Maybe I just misunderstood the 
question...

Cheers,
Norm
-- 
Norman Graham   <norman@a.cs.okstate.edu>   {cbosgd,rutgers}!okstate!norman
The opinions expressed herein do not necessarily reflect the views of
the state of Oklahoma, Oklahoma State University, OSU's Department of
Computer Science, or of the writer himself.