HttpUrlConnection

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4 total messages Started by Guillermo Tempo Thu, 23 Jul 1998 00:00

#190

Author: Guillermo Tempo
Date: Thu, 23 Jul 1998 00:00

30 lines
1573 bytes

Maybe someone can help me with this, I would really apreciate it and I thank
you in advance.

Anyway, here's a piece of code that throws an exception:

import java.net.URL;
import java.net.URLConnection;
import java.net.HttpURLConnection;
...

try {
    String serverAddress = "http://..."
    URL server = new URL(serverAddress);
    HttpURLConnection connection =
(HttpURLConnection)server.openConnection();
    ...
} catch (Exception e) {
    ...
}

The exception that I get is:
java.lang.ClassCastException: com/ms/net/wininet/http/HttpURLConnection

I think I understand why I get the exception. Is there a way around this
without having to implement HttpURLConnection and/or the StreamHandler.

Hints and comments are very welcome,
thanks.

Guillermo

Re: HttpUrlConnection

#191

Author: Tristan Austin
Date: Fri, 24 Jul 1998 00:00

67 lines
2235 bytes

Hi Guillermo

I used almost the same code and it worked fine, are you sure you've got a Http
connection there?

Guillermo Tempo wrote:


> Maybe someone can help me with this, I would really apreciate it and I thank
> you in advance.
>
> Anyway, here's a piece of code that throws an exception:
>
> import java.net.URL;
> import java.net.URLConnection;
> import java.net.HttpURLConnection;
> ...
>
> try {
>     String serverAddress = "http://..."
>     URL server = new URL(serverAddress);
>     HttpURLConnection connection =
> (HttpURLConnection)server.openConnection();
>     ...
> } catch (Exception e) {
>     ...
> }
>
> The exception that I get is:
> java.lang.ClassCastException: com/ms/net/wininet/http/HttpURLConnection
>
> I think I understand why I get the exception. Is there a way around this
> without having to implement HttpURLConnection and/or the StreamHandler.
>
> Hints and comments are very welcome,
> thanks.
>
> Guillermo
>
>





--




 Tristan Austin
 tristan.austin@dsto.defence.gov.au


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Re: HttpUrlConnection

#192

Author: cameron_cp
Date: Fri, 24 Jul 1998 00:00

24 lines
1587 bytes

In article <6p87ki$7fd$1@supernews.com>,
  "Guillermo Tempo" <Guillermo_Tempo@oti.com> wrote:
> I think I understand why I get the exception. Is there a way around this
> without having to implement HttpURLConnection and/or the StreamHandler.

==public abstract class HttpURLConnection extends URLConnection

You are correct, You will have to define

 public abstract void disconnect()
  Close the connection to the server.

 public abstract boolean usingProxy()
  Indicates if the connection is going through a proxy.



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The Idiot's Guide To Everything (ComputerRelated)
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=================================================

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Re: HttpUrlConnection

#193

Author: Guillermo Tempo
Date: Fri, 24 Jul 1998 00:00

29 lines
1855 bytes

Well, I'll have to face the inevitable...
Thanks a lot for the reply.

cameron_cp@my-dejanews.com wrote in message
<6p98is$mcd$1@nnrp1.dejanews.com>...
>In article <6p87ki$7fd$1@supernews.com>,
>  "Guillermo Tempo" <Guillermo_Tempo@oti.com> wrote:
>> I think I understand why I get the exception. Is there a way around this
>> without having to implement HttpURLConnection and/or the StreamHandler.
>
>==public abstract class HttpURLConnection extends URLConnection
>
>You are correct, You will have to define
>
> public abstract void disconnect()
>  Close the connection to the server.
>
> public abstract boolean usingProxy()
>  Indicates if the connection is going through a proxy.
>
>
>
>--
>The Idiot's Guide To Everything (ComputerRelated)
>http://members.tripod.com/~igte
>=================================================
>
>-----== Posted via Deja News, The Leader in Internet Discussion ==-----
>http://www.dejanews.com/rg_mkgrp.xp   Create Your Own Free Member Forum

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