🚀 go-pugleaf

>I have just byte[] array of 4 bytes and need to create regular InetAddress
>class.
>
>I don't know host's name and so. I only know host's IP address. I can't
>create regular
>InetAddress class, because I have to pass the name of the host to
>constructor.
>
>InetAddress inet = new InetAddress(null, array);
>is NOT solution, because InetAddress is willing to create String with null
>pointer.
>
>If I pass "" string, I can not receive host name based on IP.
>
>How can I receive host name based on IP, if I have just IP as 4 byte array
?


The only solution is:

convert your 4 byte array to string in dot convention first, then pass
to InetAddress as string. That works fine.

Sounds good ?!?!?!?! is not it.

Martin

In a previous article, "Martin Ry��nek" <rysanek@telecom.cz> said:
>I have just byte[] array of 4 bytes and need to create regular InetAddress
>class.

Sorry, but you have to convert it to a string:

    private static String   IPToString(byte[] addr)
    {
        String dottedquad = "";
        for (int i = 0; i < addr.length;)
        {
            short sh = (short)(addr[i] & 0xff);
            dottedquad += Integer.toString(sh);
            i++;
            if (i < addr.length)
                dottedquad += ".";
        }
        return dottedquad;
    }

Note that while I call it dotted*quad*, it will work in that time in the
future when the byte array is longer than 4 bytes.  (IPv6, whose time has come)

-- 
Paul Tomblin, ptomblin@xcski.com.
    "Only a NAZI would try to invoke Godwin's [law] deliberately"
        - Jeff Gostin in a.s.r