🚀 go-pugleaf

In article <4fr8be$ass@news.iconn.net>, thecrow@iconn.net says...
>
>Here is what I am trying to do, I want to find the last NON-ZERO digit of a 
>given factorial.  For instance,
>
>5! = 120
>
>so the last non-zero digit is 2.  I want to be able to do this up to 1000.  
>Problem is, no matter how huge of a data-type you use, there isn't any way for 
>the computer to handle 1000!, it is however possible to find the last non-zero 
>digit somehow.  One thing I have tried is as I went through mulitplying the 
>series of numbers in the factorial (5 * 4 * 3 * 2) I would remove all the 
>trailing ZEROS, I got this to work up to 789, but it wont work with 1000 and i 
>am not really sure why.  If anyone has a clue how I can do this let me know.

Actually, long double on INTEL or HFLOAT on the VAX will handle 1754!.

If you just want to find the final digit, after each multiplication, remove the
trailing digits by dividing by ten.  Then take a modulus with ten.  The final 
digit is going to be the result of the product of the two least significant
digits.
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