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Article #64

Re: Tough FACTORIAL math problem...

#64
From: Dik T. Winter
Date: Sun, 25 Feb 1996 23:34
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In article <312FFCCF.33209502@armory.com> Tim Martin <tass@armory.com> writes:
 > BTW-I didn't enter the competition, but I also solved it that particular
 > way...with a little more clumsy approach using strings instead of
 > longints, but the basic concept is the same - you only need to save the
 > last 4 non-zero digits, because you are only ever multiplying the result
 > by something less than 1000.

The reason you give is not the true reason.  Multiplying by 625 introduces
4 new zeros; by pure chance the fifth digit from the rightmost non-zero
digit of 624! is even (it is 0).  If it had been odd you would have found
a wrong result.  Compare: if you multiply 10016 by 625 the last non-zero
digit of the result is 6, if you had only used 0016 you would have found 1.
-- 
dik t. winter, cwi, kruislaan 413, 1098 sj  amsterdam, nederland, +31205924098
home: bovenover 215, 1025 jn  amsterdam, nederland; http://www.cwi.nl/~dik/
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References: <4gaucn$cdu@beyond.escape.com> <4gh4cq$8eo@agate.berkeley.edu> <312FFCCF.33209502@armory.com>

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Newsgroups: comp.lang.pascal.misc,comp.lang.c++,comp.lang.c,comp.lang.pascal.borland
Path: arc1-ca.pugleaf.net!cwi.nl!dik
From: dik@cwi.nl (Dik T. Winter)
Subject: Re: Tough FACTORIAL math problem...
Message-ID: <DnCutM.5ss@cwi.nl>
Sender: news@cwi.nl (The Daily Dross)
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Organization: CWI, Amsterdam
References: <4gaucn$cdu@beyond.escape.com> <4gh4cq$8eo@agate.berkeley.edu> <312FFCCF.33209502@armory.com>
Date: Sun, 25 Feb 1996 23:34:33 GMT