🚀 go-pugleaf

In article <1988Dec19.161813.788@mntgfx.mentor.com> chane@mntgfx.mentor.com (Chane Cullens  SPD Engr 526-5267) writes:
>From article <991@dogie.edu>, by edwards@dogie.edu ( Mark Edwards):
>>         t = time();
>Shouldn't this be "t = time( NULL );"

Close, and it will usually work.  But, it's not portable.  Assuming that
NULL is defined to 0, the call should be either

	t = time( (long *) NULL );

or

	t = time( (time_t *) NULL );

(I kept the uncomfortable coding style intact for consistency) depending
on whether you have the time_t typedef.  If NULL is not defined to 0, but
instead something completely wrong and warning-producing like (char *) 0,
beat the person responsible about the head and shoulders with a copy of
K&R (either edition).  If all else fails, the third possibility is

	(void) time( &t );

although this will cause some lints to say "long assignment may lose
accuracy" (hell yes, I'm trying to lose *all* the accuracy, you nitwit
program).

Oh yeah, be sure to declare t as long or time_t, whichever is more
appropriate.  The manpage shows this but lots of programmers get
complacent working on machines with 32-bit words.

Phil Kos        uunet!pyrdc!osiris!phil       The Johns Hopkins Hospital