taking a predicate name as an argument

Article View: comp.lang.prolog

Article #789

#789

From: Alisa Tannirat
Date: Thu, 12 Apr 1990 18:59

18 lines
907 bytes

how do i take a predicate name as an argument and use it as a basis for
selecting an operation on the other arguments?

for example, 

question(+, X, Y, Answer):-
  Answer is X + Y.

question(*, X, Y, Answer):-
  Answer is X * Y

i would like question to be general enough to take any operator and perform
it on X and Y resulting in Answer.

please e-mail me, the information would be appreciated.

alisa tannirat

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Path: arc1-ca.pugleaf.net!utzoo!utgpu!news-server.csri.toronto.edu!cs.utexas.edu!swrinde!zaphod.mps.ohio-state.edu!usc!orion.oac.uci.edu!eaiu088
From: eaiu088@orion.oac.uci.edu (Alisa Tannirat)
Newsgroups: comp.lang.prolog
Subject: taking a predicate name as an argument
Message-ID: <2624D004.805@orion.oac.uci.edu>
Date: 12 Apr 90 18:59:15 GMT
References: <35047@brunix.UUCP>
Reply-To: eaiu088@orion.oac.uci.edu (Alisa Tannirat)
Organization: UC Irvine Department of ICS
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