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Article #7656interupt vector table
From: Robert Mascaro
Date: Fri, 22 Jan 1993 01:21
Date: Fri, 22 Jan 1993 01:21
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I have a strong interest in writing software interupt handlers. I know that dos keeps a table of 1024 bytes from 0:0 which point to the address to jump to from servicing the interupt. My question is, I have tryed to follow the path (using debug) of interupt 1C (second clock timer), which by my calculations should be located at hex 0:70 (4 bytes per address * int number). This should contain the offset address of the handler which should point to an IRET. It seems to point to nothing. What am I doing wrong?? could someone step me through the process in DEBUG. Thankyou in advance, Rob.
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Path: arc1-ca.pugleaf.net!sparky!uunet!munnari.oz.au!uniwa!uniwa!nfm From: rmascaro@uniwa.uwa.edu.au (Robert Mascaro) Newsgroups: comp.os.msdos.programmer Subject: interupt vector table Date: 22 Jan 1993 09:21:28 +0800 Organization: The University of Western Australia Lines: 10 Message-ID: <1jni6oINNkjt@uniwa.uwa.edu.au> NNTP-Posting-Host: uniwa.uwa.edu.au X-Newsreader: Tin 1.1 PL5