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Article #7656

interupt vector table

#7656
From: Robert Mascaro
Date: Fri, 22 Jan 1993 01:21
10 lines
978 bytes
I have a strong interest in writing software interupt handlers. I know
that dos keeps a table of 1024 bytes from 0:0 which point to the address
to jump to from servicing the interupt. My question is, I have tryed to
follow the path (using debug) of interupt 1C (second clock timer), which
by my calculations should be located at hex 0:70 (4 bytes per address *
int number). This should contain the offset address of the handler which
should point to an IRET. It seems to point to nothing. What am I doing
wrong?? could someone step me through the process in DEBUG.
Thankyou in advance,
Rob.
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Path: arc1-ca.pugleaf.net!sparky!uunet!munnari.oz.au!uniwa!uniwa!nfm
From: rmascaro@uniwa.uwa.edu.au (Robert Mascaro)
Newsgroups: comp.os.msdos.programmer
Subject: interupt vector table
Date: 22 Jan 1993 09:21:28 +0800
Organization: The University of Western Australia
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