Article View: comp.sources.d
Article #2139Re: Z80 -> 8080 converter
From: Richard Klappal
Date: Mon, 19 Jan 1987 05:10
Date: Mon, 19 Jan 1987 05:10
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Not withstanding the 250 (+/-) object code combinations of the 8080
and the 796 combos for the Z-80, and (as I understand it) Intel
copyrighted the mnemonics for the 8080, preventing their use
by Zilog,
The Microsoft M-80 assembler will handle both sets of
mnemonics, (both in the same program, if desired), or
check a bulletin board for CP/M to find one of the
PD Z-80 assemblers (z80asm is one, I believe.) if your
need doesn't warrant buying one.
I speak for myself only, and have no financial interest in the
success or failure of Microsoft Corp.
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Relay-Version: version B 2.10 5/3/83; site utzoo.UUCP Path: arc1-ca.pugleaf.net!utzoo!mnetor!seismo!rutgers!ames!ucbcad!ucbvax!cbatt!ihnp4!chinet!rlk From: rlk@chinet.UUCP (Richard Klappal) Newsgroups: comp.sources.d Subject: Re: Z80 -> 8080 converter Message-ID: <1036@chinet.UUCP> Date: Mon, 19-Jan-87 00:10:47 EST Article-I.D.: chinet.1036 Posted: Mon Jan 19 00:10:47 1987 Date-Received: Tue, 20-Jan-87 04:13:30 EST References: <4010003@hpvcla.HP.COM> Reply-To: rlk@chinet.UUCP (Richard Klappal) Organization: Chinet - Public Access Unix Lines: 21