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>You can write it without a typedef like this:

>void (B::* A::var)(short) = B::Foo;

All right, so this turned out to be a compiler question to some 
extent. The solution you gave does not work under gcc version 
2.5.6: the error message is "multiple `::' terms in declarator 
invalid." It does work with some other compilers.

However, consider this: let the declaration of var be
	static void (B::*const var)(short);
within struct A. How do you perform the initialization now? Oddly 
enough, your answer still works with some compilers, even though 
these very compilers usually require that the full type of the 
variable to be initialized (var) be given at initialization time. 
I have not found a way to express the type (with "const") without 
a typedef at initialization time and I can't explain why it would 
not be required to do so.

Any ideas? Standards bug after all or common compiler bug?

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