🚀 go-pugleaf

In article <BRENNAN.92Sep3095303@yosemite.hal.com> brennan@hal.com (Dave Brennan) writes:
>I didn't have my copy of ARM handy when I posted, and I see that it also
>says is 12.4 (p. 278) "When invoked by the delete operator, memory is freed
>by the destructor for the most derived class of the object using an
>operator delete ()."
>
>What it doesn't say is which operator delete.  This tends to imply that the
>operator delete of the most derived class should be used, but as my
>previous post showed it is only used when the class being deleted has a
>virtual destructor.  This quote implies that the operator delete of the
>most derived class will be called when any object is deleted?
>
>Cany anyone clarify this?
>

	Don't make this problem harder than it really is.  Destructors and
operator delete aren't magic.  Just rephrase the question in terms of normal
functions:

	class Base
	{
	public:
	    static void operation();
	    void f() { operation(); }
	    virtual void g() { operation(); }
	};

	class Derived : public Base
	{
	public:
	    static void operation();
	    void f() { operation(); }
	    virtual void g() { operation(); }
	};

	Base *bp = new Derived;
	bp->f();	// invokes Base::f(), which calls Base::operation()
	bp->g();	// invokes Derived::g(), which calls 
			// Derived::operation()