🚀 go-pugleaf

In article 74i@ixnews3.ix.netcom.com, miker3@ix.netcom.com (Mike Rubenstein) writes:
>clamage@Eng.Sun.COM (Steve Clamage) wrote:

>>In article 95Oct26140846@avs.cs.rpi.edu, vandevod@cs.rpi.edu (David Vandevoorde
>>) writes:
>>>
>>>Would you happen to know why it must be an ``integral type''?
>>>I imagine uses for floating-point constants...

>>I believe it is because integral constant-expressions are a special item
>>in the language.  A floating-point constant-expression may consist only
>>of floating-point literals. For example, at file scope:
>>
>>	const int two = 2; // 'two' is a constant-expression
>>	int k = two; // OK
>>
>>	const double pi = 3.1415926535798;
>>	double x = pi; // error, 'pi' is not a constant-expression
>
>Am I confused?  I thought that initializers of non-aggregates could be
>any expressions, not just constant expressions and that
>
>	double x = pi;
>
>above was legal.

Gak!  No, you are correct; I managed to confuse myself. The intialization of
x is OK in C++.

The expression
	two
is a constant-expression, but the expression
	pi
is not a constant-expression, which is the point I was trying to make.
I should have quit while I was ahead :-(
---
Steve Clamage, stephen.clamage@eng.sun.com




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