🚀 go-pugleaf

In article <1992Oct31.213412.356@frumious.uucp> uunet.ca!frumious!pat writes:
| In my understanding, one of the principles of C++ is that any construct
| which has the potential to violate the type system is illegal unless
| an explicit cast is used.  So the explicit cast should be required in
| the call to f() - not because the compiler knows there is a problem,
| just because it _doesn't_ know there _isn't_.  This is exactly why
| you need an explicit cast to convert a pointer to base class to
| pointer to derived class, but not to cast from derived to base.

However, you don't need an explicit cast to go from a T* to a void*.
Hence, given that this is legal,

    T *p;
    void *q = p;

is there a good reason why this isn't?

    void f(T*);
    void (*pf)(void*) = f;

Scott

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