🚀 go-pugleaf

  Assume a class template specialization:
template <class T> class dummy {
public:
	dummy();
	dummy( const dummy<T>&);
	~dummy();

	f1( double);
	f2( int);
	f3...
..};
template <double> class dummy {
public:
	dummy();
	dummy( const dummy<T>&);
	~dummy();

	f1( double);
	f2( int);
	f3...
..};
 Assume that only member function f1 needs to be redefined.
 Have all function members f2, f3, ... to be available in the specialized
form ?
 Or can I expect that the compiler will expand them from their
template <class T> definition.
  Thank for help.
   X.Tarrago
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