🚀 go-pugleaf

>The following was taken from a copy of the DWP:
>
>  basic_string<charT,traits,Allocator>&
>      operator=(const basic_string<charT,traits,Allocator>& str);
>
>  Effects:
>    If *this and str are not the same object, modifies *this such that:
>
>                      Table 7--operator=(str) effects
>
>             +-------------------------------------------------+
>             | Element                    Value                |
>             +-------------------------------------------------+
>             |data()       points at the first element  of  an |
>             |             allocated  copy  of  the  the array |
>             |             whose first element is  pointed  at |
>             |             by str.size()                       |
>             |size()       str.size()                          |
>             |capacity()   a value at least as large as size() |
>             +-------------------------------------------------+
>    If *this and str are the same object, the member has no effect.
>  Returns:
>    *this
>
>Aside from a seeming typographical error in the Value column for Element data()
>(... by str.data() ?) the wording of this seems to rule out a counted pointer
>representation.
>
>Is my interpretation correct?
>
>-- 
>John Hickin      Bell-Northern Research, Montreal, Quebec
>(514) 765-7924   hickin@bnr.ca
>---

Because str.data() is a member function, a counted pointer implementation of
the string class could perform a copy on write at the time of the call to
str.data(). Member functions to return constant iterators, for example, need
not cause the string to be copied, so a counted pointer implementation of
the string class could still be written.  (At least, the definition of
str.data() does not rule it out, there might be something else that does.)

Paul Newson
penewson@novice.uwaterloo.ca
---
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