Article View: comp.std.c++
Article #3661Re: auto_ptr: no operator bool()?
From: Steve Willer
Date: Wed, 13 Mar 1996 23:51
Date: Wed, 13 Mar 1996 23:51
86 lines
3640 bytes
3640 bytes
James Kanze US/ESC 60/3/141 #40763 <kanze@lts.sel.alcatel.de> wrote:
>The real danger is in the following:
>
> auto_ptr< T > p1 ;
> auto_ptr< T > p2 ;
>
> if ( p1 == p2 ) ...
Well, there is obviously a solution of either modifying the way bool
works (so it can't be compared to another), or perhaps creating a new
explicit_bool type.
But what about this solution as a way to implement an auto_ptr:
class explicit_bool {
bool state_;
bool operator==(const explicit_bool &rhs) const;
bool operator!=(const explicit_bool &rhs) const;
public:
explicit_bool(bool state) { state_ = state; }
operator bool() { return state_; };
};
template <class T> class auto_ptr {
public:
/* explicit */ auto_ptr(T *p=0): pointee(p) {}
// template<class U> auto_ptr(auto_ptr<U> &rhs):
pointee(rhs.release()) {}
auto_ptr(auto_ptr<T> &rhs): pointee(rhs.release()) {}
~auto_ptr() { delete pointee; }
// template<class U> auto_ptr<T>& operator=(auto_ptr<U> &rhs) {
auto_ptr<T> &operator=(auto_ptr<T> &rhs) {
if (this != &rhs) reset(rhs.release());
return *this;
}
T& operator*() const {return *pointee;}
T* operator->() const {return pointee;}
T* get() const {return pointee;}
T* release() {
T *oldPointee = pointee;
pointee = 0;
return oldPointee;
}
operator explicit_bool() { return explicit_bool(pointee != 0); }
explicit_bool operator!() { return explicit_bool(pointee == 0); }
// operator bool() {return (pointee != 0);} // apparently not part
of the std
// bool operator!() {return (pointee == 0);} // ditto
void reset(T *p=0) {delete pointee; pointee = p;}
private:
T *pointee;
};
class myclass{};
int main(char,char**) {
auto_ptr<myclass> a1,a2;
a1 = a2;
a1 == a2;
a1 != a2;
if (a1);
if (!a1);
return 0;
}
To tell you the truth, I'm not 100% sure this would work properly,
because I don't have my C++ books here (I'm at home sick), and my
compiler doesn't have "bool" as a built-in type (it's a class). With
my current compiler, the "a1==a2" and "a1!=a2" lines don't work
(illegal structure operation), which is exactly how I'd expect it. The
"if (a1)" line doesn't compile either, but wouldn't it work if "bool"
was a built-in type? This would mean an implicit conversion to
explicit_bool and then to bool, but my (somewhat faulty) memory is
that that's legal.
Even if that's not legal, what about defining "template <class T>
template<class U>auto_ptr<T>::operator==(const auto_ptr<U>& rhs)" and
the equivalent operator!= as private?
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From: willer@interlog.com (Steve Willer) Message-ID: <31474cd9.10139718@news.interlog.com> X-Original-Date: Wed, 13 Mar 1996 23:02:38 GMT Path: arc1-ca.pugleaf.net!in2.uu.net!bounce-back Date: 13 Mar 96 23:51:30 GMT Approved: fjh@cs.mu.oz.au Newsgroups: comp.std.c++ Subject: Re: auto_ptr: no operator bool()? Organization: InterLog Internet Services References: <313ddfd9.16044605@sqarc.sq.com> <4i2jqr$8dl@solutions.solon.com> X-Newsreader: Forte Agent .99d/32.182 X-Auth: PGPMoose V1.1 PGP comp.std.c++ iQBFAgUBMUdfkeEDnX0m9pzZAQH2uwF+Icw5iWYz8a+Hpaq0j7UrXEG3euLSNN6/ jiPMFV3llZbbvfqetuNOE5WM03j+B/6c =VgJR