"explicit" default constructor?

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Article #3823

#3823

From: Roman Lechtchinsky
Date: Wed, 27 Mar 1996 03:07

21 lines
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Hi,

as I read the section [class.conv.ctor] of the DWP, I get the impression that 
the description of converting and non-converting constructors applies to all 
constructors, i.e. a constructor is either converting or non-converting. A 
non-converting constructor creates an object "only where a constructor call 
is  explicitly  indicated by the syntax". This has no implications on 
constructors with more than one parameter, but what about the default 
constructor? Should a default constructor call be really indicated by the 
syntax and if so, how is it to be done? What if the default constructor is 
declared "explicit"? 

Bye

Roman
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Path: arc1-ca.pugleaf.net!cs.mu.OZ.AU!bounce-back
From: Roman Lechtchinsky <wolfro@cs.tu-berlin.de>
Newsgroups: comp.std.c++
Subject: "explicit" default constructor?
Date: 27 Mar 96 03:07:56 GMT
Organization: Technical University of Berlin
Approved: fjh@cs.mu.oz.au
Message-ID: <31588662.F1@cs.tu-berlin.de>
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