🚀 go-pugleaf

/*
The following program displays "Borland" when run under Borland C++
and "Microsoft" when run under Microsoft C++. The reason is that
Borland uses the user defined version of operator= whereas Microsoft
uses the default =. I presume the AT&T compiler and G++ will follow
Borland.

I can't find a revelant statement in the ARM or C++ reference manual.
So who is right, or is this a matter for the standards committee?

(Apologies if this has already been discussed to death)

Robert
*/



#include <iostream.h>

char* borland = "Borland";
char* microsoft = "Microsoft";

class Base
{
public:
   char* c;
   Base() { c = microsoft; }
};

class Derived : public Base
{
public:
   void operator=(const Base&) { c = borland; }
   Derived() {}
};

main()
{
   Derived d,e;
   e = d;                          // Borland uses operator= whereas
                                   // Microsoft uses the default =
   cout << e.c;
   return 0;
}