Calling exit() from the dtor of a static object

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2 total messages Started by David A Smallberg Wed, 25 Oct 1995 02:36

#2296

Author: David A Smallberg
Date: Wed, 25 Oct 1995 02:36

27 lines
1290 bytes

Although I know what some implementations do, I can't determine from
the Working Paper what should happen in this case:

	int n = 0;

	struct X {
		~X() { exit(++n); }
	};

	X a;
	X b;
	int main()
	{
		exit(n);
	}

Does the destructor for "a" get called?  Is the exit status 0, 1, or 2?
On the implementations I have tried, the dtor for "b" (but not "a")
gets called, and the exit status is 1.  I see nothing in the WP that
says that the dtor for "a" must not be called (or must be called, for that
matter).

Any pointers?
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Re: Calling exit() from the dtor of a static object

#2302

Author: Simon Tooke
Date: Wed, 25 Oct 1995 17:33

51 lines
1919 bytes


In <951024.195404z.11077.das@lanai.cs.ucla.edu> David A Smallberg <das@CS.UCLA.EDU> writes:

>Although I know what some implementations do, I can't determine from
>the Working Paper what should happen in this case:

>	int n = 0;

>	struct X {
>		~X() { exit(++n); }
>	};

>	X a;
>	X b;
>	int main()
>	{
>		exit(n);
>	}

>Does the destructor for "a" get called?  Is the exit status 0, 1, or 2?
>On the implementations I have tried, the dtor for "b" (but not "a")
>gets called, and the exit status is 1.  I see nothing in the WP that
>says that the dtor for "a" must not be called (or must be called, for that
>matter).

>Any pointers?

The C++ Working paper only specifies "additional" behaviour for exit() - it
refers to ISO C exit() for basic behaviour, and the ISO C standard
states

	"if more than one call to exit() is executed by a program, 
	 the result is undefined".

I'd have to say you're living on the edge.

-simon tooke

===============================================================================
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