Re: [m]allocation question

Article View: comp.std.c

Article #1758

#1758

From: Stephen Clamage
Date: Sat, 29 Sep 1990 17:43

19 lines
1165 bytes

cameron@usage.csd.oz (Cameron Simpson,Uhmmm..???? Who knows) writes:

>I have been using the macro

>    /* size of a field - may break under ANSI, but hasn't yet */
>    #define		fsizeof(type,field) sizeof(((type *)NULL)->field)

>for some time. I have recollections of remarks to the effect that the
>above locution could break under a conformant compiler. Could someone
>either correct me ("yes, Cameron, fsizeof() is ok") or re-iterate the
>explaination of why this macro can break, while sizeof(*t) is fine.

As long as "type" in not an incomplete type and "field" is not a bit
field, this is perfectly fine.  The ANSI C standard explicitly
states that the expression argument of sizeof is not evaluated, so
NULL will not be derefrenced (which would be illegal).
-- 

Steve Clamage, TauMetric Corp, steve@taumet.com

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Path: arc1-ca.pugleaf.net!utzoo!attcan!uunet!taumet!steve
From: steve@taumet.com (Stephen Clamage)
Newsgroups: comp.std.c
Subject: Re: [m]allocation question
Message-ID: <466@taumet.com>
Date: 29 Sep 90 17:43:49 GMT
References: <13946@smoke.BRL.MIL> <871@usage.csd.unsw.oz.au>
Organization: Taumetric Corporation, San Diego
Lines: 19

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