🚀 go-pugleaf

In article <17583@ksr.com> jfw@ksr.com (John F. Woods) writes:
|jos@and.nl (Jos Horsmeier) writes:
|>On (normal?) two complement implementations nothing happens, i.e.
|>the bit pattern remains the same as it was. If the size of an
|>unsigned int is larger than the size of a signed int, there will
|>occur sign bit extension, e.g. sizeof(int) = 2; sizeof(unsigned int) = 4.
|
|3.1.2.5 Types "For each of the signed integer types, there is a corresponding
|(but different) _unsigned integer type_ (designated with the keyword
|*unsigned*) that uses the same amount of storage (including sign information)
|and has the same alignment requirements."

Ah, yes. I was a bit sloppy by saying it that way. I should have written
something like: `If the size of an unsigned integral type is larger than
the size of the original signed integral number ... '. This applies to:

short int i= -1;
unsigned long l;

l= (unsigned long)i;

kind regards,

Jos aka jos@and.nl