🚀 go-pugleaf

smclewin@ultrix.ramapo.edu (Scooter McLune) writes:
>donne@imec.be (Werner Donne) writes:
>>int
>>main(void)
>>{
>>  const char **a;
>>  char **b;
>>  a = b;
>>  return 0;
>>}

>The assignment cannot be done because **a is a constant variable, by your
>definition.  If you were to do the assignment "b = a" with the code you
>have above, there would be no problem.

No.  "b = a;" is illegal for the same reason "a = b;" is; the two objects
are not pointers to compatible types (const char * is not compatible with
char *). 

Your first sentence is confusing; are you arguing that a is constant (false,
that would be "char ** const a"), or that "a = b;" somehow would modify the
const object at **a (false)?