Article View: comp.std.c
Article #2486int (*f)(void) = 0; int (*f)(void) = (void *) 0;
From: Earl Chew
Date: Tue, 26 Feb 1991 21:39
Date: Tue, 26 Feb 1991 21:39
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974 bytes
The standard states that 0 and (void *) 0 are `null pointers'. Does this mean that they are equivalent in all contexts? Specifically: int (*f)(void) = 0; My understanding is that this is permissible. int (*f)(void) = (void *) 0; I am unsure whether this is permissible. Earl -- Earl Chew, Dept of Computer Science, Monash University, Australia 3168 EMAIL: cechew@bruce.cs.monash.edu.au PHONE: 03 5655778 FAX: 03 5655146 ----------------------------------------------------------------------
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arc1-ca.pugleaf.net!utzoo!utgpu!news-server.csri.toronto.edu!cs.utexas.edu!sun-barr!olivea!uunet!munnari.oz.au!bruce!sol1!cechewShow Full Headers
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Path: arc1-ca.pugleaf.net!utzoo!utgpu!news-server.csri.toronto.edu!cs.utexas.edu!sun-barr!olivea!uunet!munnari.oz.au!bruce!sol1!cechew From: cechew@sol1.cs.monash.edu.au (Earl Chew) Newsgroups: comp.std.c Subject: int (*f)(void) = 0; int (*f)(void) = (void *) 0; Summary: Assigning null pointers to function pointers Keywords: function pointers, null pointers Message-ID: <cechew.667604378@sol1> Date: 26 Feb 91 21:39:38 GMT Sender: news@bruce.cs.monash.OZ.AU Lines: 16