Re: More Re: Function Argument Evaluation argument

Article View: comp.std.c

Article #2659

#2659

From: Roy Johnson
Date: Mon, 01 Apr 1991 20:21

30 lines
1292 bytes

I understand that the comma operator is a sequence point.
If we use the comma operator as a sequence point between evaluations:

   int v=1;
   printf("%d %d\n", (1, v), (1,v++));

This can print
	1 1
or
	2 1
if I understand it right, which I very well may not.

Similarly,

   char *x="foo", *y="bar", *p;
   p=x;
   printf("%s %s\n", (1, (p=y)), (1, p));

can print

	foo bar
or

	bar bar

Do I win?  8^)
--
======= !{sun,psuvax1,bcm,rice,decwrl,cs.utexas.edu}!shell!rjohnson =======
Feel free to correct me, but don't preface your correction with "BZZT!"
Roy Johnson, Shell Development Company

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From: rjohnson@shell.com (Roy Johnson)
Newsgroups: comp.std.c
Subject: Re: More Re: Function Argument Evaluation argument
Message-ID: <RJOHNSON.91Apr1142143@olorin.shell.com>
Date: 1 Apr 91 20:21:43 GMT
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In-Reply-To: bhoughto@pima.intel.com's message of 29 Mar 91 06:13:49 GMT

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