🚀 go-pugleaf

In article <4g55fl$avl@solutions.solon.com>,  <msb@sq.com> wrote:
>> > short test(short x1, short x2) {
>> >  short result;
>> >  result = x1 + x2;
>> 
>> The addition operator "+" converts your short operands to ints.
>
>No, just using their values does that.  The operator + never sees
>operands narrower than int.  In the statement
>	x1; 
>the short is converted to int before being discarded.

Okay, I'm confused.  Let just say the above is true.  Then the expression
"x1 + x2" has type int because x1 and x2 were converted to int before
being passed to the + operator.

So what if sizeof(short) == sizeof(int)?  Assuming both x1 and x2 are
non-negative, would "x1 + x2" be unsigned int if it wouldn't fit in an
int?  In short, would there be undefined/implementation defined behaviour
if "result" is unsigned int?  How about long?

sl14@cornell.edu
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