🚀 go-pugleaf

In article <4g28hr$qko@solutions.solon.com> thads@csn.net (Thad Smith)
writes: 
<snip>
   In article <4fvgrm$dv9@solutions.solon.com>, msb@sq.com wrote:
   >Oh dear, I have to correct Chris Torek (torek@bsdi.com).  

   >Thus even in ANSI C, if this function is called this way:
   >
   >	extern short p, q, r, test(short,short);
   >	r = test(p,q);
   >
   >the values from p and q are still converted from short to int and back
   >to short.  

   I find nothing in the Standard that states that the arguments undergo
   integral promotions before being assigned to the function parameters.

The way I read the standard (6.2.1.1):

``A char, a short int, or an int bit-field, or their signed or unsigned
varieties, or an enumeration type, may be used in an expression
wherever an int or unsigned int may be used. ...< describing integral
promotions >... these are called integral promotions.''

Seems to imply that whenever a value of type `int' is a possibility,
integral promotions always take place. Without enum types, I don't see
how this matters in a function call, as long as implementation defined
behaviour is reasonable (i.e. signed char->int->short is same as
signed char->short etc.)

For enums, I am confused. If an enum type is compatible with `long',
does integral _promotion_ narrow it to an int or unsigned int :-)?

Cheers
Tanmoy
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