🚀 go-pugleaf

-=> Quoting William Wendling to All <=-

 WW> From: wendling@eagle.uis.edu (William Wendling)
 WW> Organization: Sangamon State University

 WW> Mike Chilcott (mikechil@cris.com) wrote:
 WW> }    I am new at programming, and have a little problem.
 WW> } I have a huge file (over 90+meg). It is broken down into
 WW> } records of 923 characters each. Each record consists of 
 WW> } 30+ fields of varying size lengths.

 WW> }    I want to open the file, read a record and assign each 
 WW> } field a variable name. I then want to open an output file,
 WW> } and write certain fields to it.

 WW> }    I have been told to try and use STRUCTS, but am 
 WW> } having problems, understanding and implementing.
 WW> } Any help is appreciated....

I am new to C myself, but the basics don't change between languages much.

What you want to do is open the file in BINARY mode.
I am not sure the exact syntax but the example below should give you the idea.

struct MYFILE
{
  char FirstField[30];  /* Whatever size you need as character */
  int SecondField;  /* 2 bytes as integer */
  char ThirdField[891];         /* once you have accounted for all the _
        fields you close your struct */
};

now you just use your struct MYFILE to read in blocks from the file, and then
just access your variables in the struct like this

char NAME[30];
int NumberOfChildren;

NAME = MYFILE.FirstField;
NumberOfChildren = MYFILE.SecondField;

this should give you an idea of how to handle your file with structs, I would
like to give you more info, but I am new to C myself.

-={Dave Reid}=- 

... A feature is a bug with seniority.

___ Blue Wave/QWK v2.20 [NR]