🚀 go-pugleaf

In article <40rjdn$jof@solutions.solon.com> seebs@solutions.solon.com
(Peter Seebach) writes
<> On a related note, how can one determine the maximum number of digits one
<> will need to print an integer?  All modern programmers are, of course,
<> making sure that sprintf() destination strings have enough characters.
<> Is there a portable way to define "enough characters"?

Well, log 10(2) = .30103-.  If we hav an 'int'-variant 'T', this is enough:
	(sizeof(T) * CHAR_BIT + 2) / 3 + 2
.  Goind from binarie to decimal one doth better to make the ratio greater
than the logarithm, 1/3 (or 28/93 = .301075+).  From decimal to binarie
3/10 (that is, 10/3) is enough.  But when I know that CHAR_BIT is 8, I uze
	(sizeof(T) * 5 + 1) / 2 + 2
, for 5/2 is enoughlie greater than (3/10) x 8 = 12/5 .  Theze work just as
well for 'float's in "E"-format, except that one needs to add more than 2,
for the "E" and the signs and the uprounding for, in effect, twain integers
and not one.