🚀 go-pugleaf

In article <1995Sep7.094751.4404@dcs.warwick.ac.uk>,
Zefram <A.Main@dcs.warwick.ac.uk> wrote:
>John Winters <john@polo.demon.co.uk> wrote:
>>Or indeed, as :
>>
>>const char __foo[] = {'H','e','l','l','o',' ','w','o','r','l','d','\0'};
>>char *foo;
>>const char *bar;
>>foo = (char *) __foo;
>>bar = (const char *) __foo;
>
>Indeed.  That's the effect of the const.
>

Not quite.  That's the effect of them being two identical string literals.
The compiler is entitled to coalesce the string literals
whether or not the things pointing to them are const.  (Or perhaps
you meant one of the later consts?)

John
-- 
John Winters.  Wallingford, Oxon, England.